Question

What is the equation of the line that passes through the point (-2,-3) and has a slope of -1?

Answer 1

`\huge\boxed{\sf{y=-x-5}}`

Explanation:

Hello.

First, let's write the equation in Point-Slope form:

y-y1=m(x-x1)

Where

y1 = the y-coordinate of the point (in this case, it's -3)

m = slope (in this case, it's -1)

x1 = the x-coordinate of the point (in this case, it's -2)

Now that we know what each variable stands for, let's write the equation:

y-(-3)=-1(x-(-2)

y+3=-(x+2)

Convert into slope-intercept form (y=mx+b):

y+3=-x-2

Subtract 3 from both sides:

y+3-3=-x-2-3

y=-x-5

And we're done!

I hope it helps & have an outstanding day! :)

`\boxed{imperturbability}`