Question

Simplify

Help me please

Answer 1

`(-27b^(6))/(c^(18))`

Explanation:

first distribute the ^3, -3^3=-27, for the variables, (x^y)^3=x^(3y) so (b^2)^3=b^6 and (c^-6)^3=c^-18. now we have
`-27b^(6)c^(-18)`. Next we have to get rid of the negative in c^-18. x^-y=1/x^y so c^-18=
`(1)/(c^(18))`, plug it in and you get
`(-27b^(6))/(c^(18))`