106k views
5 votes
Factor by grouping.

12x+12y+bx+by

User Aashanand
by
7.9k points

2 Answers

5 votes


\\ \rm\rightarrowtail 12x+12y+bx+by

  • Take 12 common


\\ \rm\rightarrowtail 12(x+y)+bx+by

  • Take b common


\\ \rm\rightarrowtail 12(x+y)+b(x+y)


\\ \rm\rightarrowtail (12+b)(x+y)

User Jovan
by
7.8k points
6 votes

Answer: (12+b)(x+y)

Explanation:

The terms 12x and 'bx' share a common factor of 'x'. Therefore, we can group them together. The terms 12y and 'by' also share a term of 'y', so we can group them together too:


12x+12y+bx+by


12x+bx+12y+by

Factor out an 'x' from the first two terms to get:


x(12+b)+12y+by

Now, factor out a 'y' from the last two terms to get:


x(12+b)+y(12+b)

Since the quantities inside of the parenthesis are the exact same, we can also factor out the entire term (12+b) to get:


(12+b)[x+y]

User Selvarajmas
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories