Question

Suppose y varies inversely with x, and y = 32 when x = 4. What is the value of y when x = 8?

a. 1/8
b. 64
c. 16
d. 8

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Answer 1

16

Explanation:

Inverse variation is of the form

xy = k where k is a constant

x=4 and y = 32

4*32 = k

128 = k

xy = 128

Let x = 8

8y = 128

Divide each side by 8

8y/8 = 128/8

y =16