Question

Please help me answer this question?

Answer 1

`P'(x)=2.2-0.12x`

Explanation:

start by finding
`P(x) = R(x)-C(x)`

`P(x)=3x-0.06x^2-286-0.8x`

to find P'(x), you take the derivative of P(x)

`P'(x)=(d)/(dx) (2.2x-286-0.06x^2)`

`(d)/(dx) (2.2x-286-0.06x^2)=2.2-0.12x`

so
`P'(x)=2.2-0.12x`