Work out the given expression (6x²y³-3xy⁴)÷3xy²

asked Aug 20, 2022 154k views

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3 votes

Answer:

$\frac{3x {y}^(2) (2xy - {y}^(2) )}{3x {y}^(2) } \\ 2xy - {y}^(2)$

Pato Loco answered Aug 23, 2022

5.3k points

1 vote

Answer:

$\boxed{=y(2x-y)}$

Explanation:

$(6x^2y^3-3xy^4)/(3xy^2) \\\\=(3xy^3(2x-y))/(3xy^2) \\\\=y(2x-y)\\\\=2xy-y^2$

Jonsidnell answered Aug 27, 2022

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