Question

(Ight ima need some help!! ) solve the following equation (2x + 3) (3x + 2) − (3x + 2) (2x− 3) = 0. solve for x and show work

(2x + 3) (3x + 2) − (3x + 2) (2x− 3) = 0

Answer 1

x =
`-(2)/(3)`

Explanation:

I used the FOIL method

[(2x + 3) (3x + 2)] − [(3x + 2) (2x− 3)] = 0

`(6x^(2) +4x+9x+6) - (6x^(2) -9x+4x-6)=0`

`(6x^(2) +13x+6) - (6x^(2) -5x-6)=0`

`(6x^(2) +13x+6) - 6x^(2) +5x+6=0`

combine like terms

`6x^(2) -6x^(2) = 0`

`13x+5x=18x`

`6+6=12`

so,
`18x +12 = 0`

subtract 12 on both sides

`18x=-12`

divide by 18 to isolate x

`x=-(12)/(18)`

and simplifies to

`x=-(2)/(3)`