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A position of a particle moving on an x axis is given by x=7•4 + 9•2t - 2•1 t^3, with x in meters and t in seconds. what is its velocity at t=3•5s? is the velocity,or is it Continuously changing?​

User Chandan H
by
8.4k points

1 Answer

5 votes

Answer:

The velocity at that time would be
(-67.975\; \rm s). The velocity of this particle is continuously changing.

Step-by-step explanation:

Differentiate the expression for position
x with respect to time
t to find an expression for velocity.


\begin{aligned}v(t) &= (d)/(dt)[x(t)] \\ &= (d)/(dt) \left[ 7.4 + 9.2\, t - 2.1\, t^(3)\right]\\ &= 9.2 - 6.3\, t^(2)\end{aligned}.

Hence, at
t = 3.5\; \rm s, velocity would be
v(3.5) = 9.2 - 6.3 * (3.5)^(2) = -67.975\; \rm m.

Since velocity
v(t) changes with time
t, the velocity of this particle is continuously changing.

User Ius
by
8.1k points

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