Question

Help me please


`( \cos(80) )/( \sin(10) ) + ( \sin(20) )/( \cos(70) ) = 2 \\ \\ ( \cot(40) )/( \tan(50) ) + ( \cos(65) )/( \sin(115) ) = 2`
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Answer 1

`( \cos(80) )/( \sin(10) ) + ( \sin(20) )/( \cos(70) ) = 2 \\ ( \cos(90 - 10) )/( \sin(10) ) + ( \sin(20) )/( \cos(9 0 - 20) ) = 2 \\ ( \sin(10) )/( \sin(10) ) + ( \sin(20) )/( \sin(20) ) = 2 \\ 1 + 1 = 2 \\ 2 = 2 \\ \\ ( \cot(40) )/( \tan(50) ) + ( \cos(65) )/( \sin(115) ) = 2 \\ ( \cot(90 - 50) )/( \tan(50) ) + ( \cos(65) )/( \sin(90 + 65) ) = 2 \\ ( \tan(50) )/( \tan(50) ) + ( \cos(65) )/( \cos(65) ) = 2 \\ 1 + 1 \\ = 2`