Question

Anybody good in math?

Answer 1

The easiest and most time-effective way to approach this problem is to use the quadratic formula:

`x=(-b\pm√( b^2-4ac))/(2a)`,

where a = 2, b = -1, and c = 4. (We get this from the general quadratic: ax² + bx + c.)

When we plug in our numbers, we get
`x=(1\pm√(1-32))/(4)` which also equals
`(1\pm i√(31))/(4)`, or the first choice!

:)

Answer 2

im good

Explanation: