Question

URGENT- A rectangle has an area of 210 cm 2 and a perimeter of 58 cm. What are its dimensions? (show work)

Answer 1

L= 29-b

Explanation:

A=210cm^2

A= L*b

210= (29-b) b

210= 29b-b^2

b^2-29b+210=0

b^2-15b-14b+210=0

b(b-15)-14(b-15)=0

(b-15)(b-14)=0

R=14 B=15

P-58cm

p=2(l+b)

58=2(l+b)

29= l+b

L= 29-b