Question

Trigonometry help needed
help would be appreciated ​

Answer 1

Explanation:

Question 5

Part A

if Sin(x) = - 3/5 and tan(x) < 0

you are told 3 things

1. cos(x) must be plus because there are 4 quads. Everybody is plus in quad 1. Sin and tan are <0 so you must be in quad 4 where cos(x) => 0
2. From sin^2(x) + cos^2(x) = 1, we get that cos(x) = 4/5
3. Tan(x) = sin(x) / cos(x)

tan(x) = Sin(x)/cos(x)

tan(x) = -3/5 // 4/5

Tan(x) = -3/4

Part B

cos(2x) = cos^2(x) - sin^2(x)

cos(2x) = (4/5)^2 - (-3/5)^2

cos(2x) = 16/25 - 9/25

cos(2x) = 7/25

Part B

x + y = 90

sin(x +y) = 1

Sin(x - y) =

Sorry can't do this part. I don't know what this is equal to.