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a 100 kg crate,sliding on a floor, is brought to a stop by 25 N force what is the deceleration of the crate
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a 100 kg crate,sliding on a floor, is brought to a stop by 25 N force what is the deceleration of the crate

User Mansuetus
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4.0k points

2 Answers

13 votes

Answer:

25neuton+100kg =125kg floor sliding

User Iskander
by
4.3k points
10 votes

Step-by-step explanation:

a = ?

m = 100kg

Force = 25N

F = ma

a = F/m

a = 25/100

a = ¼

a = 0.25ms—²

deceleration = negative acceleration

deceleration = —0.25ms—²

User Sayonti
by
3.9k points
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