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If the areas of the given pairs of shapes are equal, find the value of x.​

If the areas of the given pairs of shapes are equal, find the value of x.​-example-1
User Digicrat
by
7.4k points

2 Answers

3 votes

Answer:

X= 8cm

Explanation:

area of the square = s×s = 16×16 = 256cm

area of the rectangle = l×b = 32×x = 32x

Given , area of triangle = area of square

32x = 256

x= 256/32

x= 8cm

User Raconteur
by
7.8k points
2 votes

Answer:


x = 8cm

Explanation:

we are given a square and rectangle.we want to figure out x which is the width of the rectangle. we are also given a condition i.e

  • the area of the square equal to the area of the rectangle

therefore,


\displaystyle \rm A _(square ) = A _(rect)

recall the formula of the area of square and rectangle so,


\displaystyle {s}^(2) = lw

now assign variables


  • s \implies16cm

  • l \implies32cm

  • w \implies x

thus substitute:


\displaystyle 32cmx = {16cm}^(2)

simplify square:


\displaystyle 32cmx = 256cm^2

divide both sides by 32:


\displaystyle \boxed{x = 8cm}

and we're done!

User Brynn McCullagh
by
8.3k points

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