Question

Find the lengths of AD, EF, and BC in the trapezoid below.

Answer 1

We know that,

`EF=(AD+BC)/(2)`

which is

`x=(x-5+2x-4)/(2)`

Now solve for x,

`x=(3x-9)/(2)`

`2x=3x-9`

`x=9`

Since x is 9, the lengths are,

`AD=x-5=9-5=\boxed{4}`

`EF=x=\boxed{9}`

`BC=2x-4=18-4=\boxed{14}`

Hope this helps :)