Question

Question is posted below

Answer 1

-120/169

Explanation:

`sin(\theta) = \pm\sqrt{1-\cos^2{\theta}}=\pm\sqrt{1-((5)/(13))^2}=\pm\sqrt{1-(25)/(169)}=\pm\sqrt{(144)/(169)}=\pm(12)/(13)`

In Quadrant IV, sinθ < 0

so sinθ = -12/13

sin2θ = 2 sinθ cosθ = 2 (5/13) (-12/13) = -120/169