Question

What is an equation of the line that passes through the points (-6, -8) and (-3,-3)?​

Answer 1

Given points

• (-6,-8)
• (-3,-3)

First find the slope

`\boxed{\sf m=(y_2-y_1)/(x_2-x_1)}`

`\\ \sf\longmapsto m=(-3+8)/(-3+6)`

`\\ \sf\longmapsto m=(5)/(3)`

Now

`\boxed{\sf y=mx+b}`

`\\ \sf\longmapsto -3=(5)/(3)(-3)+b`

`\\ \sf\longmapsto b=2`

Hence the equation will be

`\\ \sf\longmapsto y=(5)/(3)x+2`

Answer 2

y = 5/3x+2

Explanation:

First find the slope

m = ( y2-y1)/(x2-x1)

= ( -3 - -8)/( -3 - -6)

= ( -3+8) / (-3+6)

= 5/3

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

Substituting the point (-3,-3)

-3 = 5/3(-3) + b

-3 = -5+b

-3+5 = b

2 = b

y = 5/3x+2