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PLEASE HELP ASAPPPPPPPPPPPPPPPPPPPPPPP

IF ray ST bisects ∠VSU, m∠VST = 6z+3, and m∠TSU = 3(z+12), calculate m∠VSU. Assume that point T is on the interior of ∠VSU.

User Andrewk
by
2.9k points

2 Answers

2 votes

Answer:

138 degrees

Explanation:

6x+3=3(x+12)

6x+3=3x+36

3x=33

x=11

we plug in 11 to the equations...

6(11)+3=69

3(11+12)=69

Now we add them together..

69+69=138

:) ask me if you have any further questions

User Idstam
by
3.6k points
3 votes

Answer:

∠VSU = 138°

Explanation:

ST bisects ∠VSU

So, ∠VST = ∠TSU

6z + 3 = 3(z + 12)

6z + 3 = 3z + 3*12 {distributive property}

6z + 3 = 3z + 36 {Subtract 3 from both sides}

6z = 3z + 36 - 3

6z = 3z + 33 {Subtract 3x from both sides}

6z - 3z = 33

3z = 33 {Divide both sides by 3}

z = 33/3

z = 11

∠VST = 6z + 3 = 6 *11 + 3

= 66 + 3

= 69

∠VSU = 69 + 69 = 138°

PLEASE HELP ASAPPPPPPPPPPPPPPPPPPPPPPP IF ray ST bisects ∠VSU, m∠VST = 6z+3, and m-example-1
User Kokul Jose
by
3.3k points