Question

Can anyone help? It’s due in the morning

Answer 1

21) Angle 4

Angle 5

Angle GVH

Angle GVI

Angle HVI

22) Area of parallelogram =
`bh`

A = 9 × 4 =
`36mi^2`

23) Area of a triangle =
`(1)/(2) bh`

A =
`(1)/(2) (12)(7.3)`

A =
`43.8m^2`

24) Distance between each pair of point:

Distance between two points =
`\sqrt{(x_(B)-x_(A) )^2+(y_(B)-y_(A) )}`

Add the values in the formula & solve:

`=√((-2-0)^2+(2--4)^2)`

`=√((-2)^2+6^2)`

`=√(4+36)`

`=√(40)=6.3246`

25) Midpoint
`(x_(M),y_(M) )=(\frac{x_(A) -x_(B) } {2} ,(y_(A)+y_(B) )/(2) )`

`=((10+0)/(2),(6+7)/(2) )`

`=((10)/(2) ,(13)/(2) )`

Midpoint of a line segment
`(x_(M),y_(M) )=(5,6.5)`

I hope this helps....