Question

The rate of diffusion of gas A is double the rate of gas B. The ratio of their molecular weight is​

Answer 1

Ratio is 4:1

Step-by-step explanation:

from graham's law of gaseous diffusion:

`{ \bf{ (R _(A) )/(R_(B) ) = \sqrt{ (M_(A) )/(M_(B)) } }}`

but Ra = 2Rb:

`{ \sf{ ((2)/(1) ) {}^(2) = (M _(A))/(M _(B) ) }} \\ \\ { \sf{(M _(A))/(M _(B) ) = (4)/(1) }} \\ \\ {M _(A)} : {M _(B) } = 4 :1`