39.9k views
0 votes
Suppose h” is continuous at x = 2,h' (2) = 0, and h” (2) < 0.

What can you say about the behavior of h at X = 2?

User Tonys
by
7.9k points

1 Answer

3 votes

Answer:

Hello,

Explanation:

h(x) has a minimum at x= 2. (h(x) is turning down at x=2)

I have suppose that h''(2 + ) <0 and h''(2 -) <0

User Paramount
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories