Question

(cos θ) ( sin 2θ) -2 sin θ +2 =0

Answer 1

`(cos \:\theta )(sin\: 2\theta)-2\:sin\: \theta +2=0`
`\Longleftarrow` substitute

`sin\: \theta \: cos^(2) -sin \theta +1=0`
`\Longleftarrow` Divide both sides by 2

`sin\theta (cos^(2) \theta -1)+1=0`
`\Longleftarrow` Factor

`sin \theta (sin^(2) \theta )+1=0`
`\Longleftarrow` substitute

`sin^(3) \theta =-1`
`\Longleftarrow` Isolate

`sin \theta =-1`

`\theta =(3\pi )/(2) ,(7\pi )/(2)`

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