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M/HCB = 60°, m/DCB = 9x-1, and m/DCH = 2x+ 16. Find x​

M/HCB = 60°, m/DCB = 9x-1, and m/DCH = 2x+ 16. Find x​-example-1

2 Answers

5 votes

Answer:

x=11

Explanation:

<DCB = <DCH + < HCB

9x-1 = 2x+16 + 60

Combine like terms

9x-1 = 2x+76

Subtract 2x from each side

9x-1-2x= 2x+76-2x

7x-1 = 76

Add 1 to each side

7x-1 +1 = 76+1

7x = 77

Divide by 7

7x/7 = 77/7

x=11

User Howanghk
by
3.8k points
3 votes

Answer:


x=11

Explanation:

Note that ∠DCB is the sum of ∠HCB and ∠DCH. Hence:


m\angle DCB = m\angle HCB + m\angle DCH

Substitute in the appropriate values/expressions:


(9x-1) = (60) + (2x+16)

Solve for x. Combine like terms:


9x - 1 = 2x + 76

Subtract 2x from both sides:


7x - 1 = 76

Add one to both sides:


7x = 77

And divide. Hence:


x=11

User Apinanyogaratnam
by
3.5k points