Question

The width of a rectangle is three units less than the length if the area is 28 square units then find the dimensions of the rectangle

Answer 1

Let

• width be x
• Length=x+3

ATQ

`\\ \sf \longmapsto Area=Length* Width`

`\\ \sf \longmapsto x(x+3)=28`

`\\ \sf \longmapsto x^2+3x=28`

`\\ \sf \longmapsto x^2+3x-28=0`

`\\ \sf \longmapsto x^2+7x-4x-28=0`

`\\ \sf \longmapsto x(x+7)-4(x+7)=0`

`\\ \sf \longmapsto (x-4)(x+7)=0`

`\\ \sf \longmapsto x=4\:or\:x=-7`

• Ignore negative value

`\\ \sf \longmapsto Width=4units`

`\\ \sf \longmapsto Length=4+3=7units`