Question

Can someone help me on this please

Answer 1

x = 1 and x = 2

Explanation:

`{x}^(5) - 5 {x}^(3) = - 4x \\ {x}^(4) - 5 {x}^(2) + 4 = 0 \\ ( {x}^(2) - 4)( {x}^(2) - 1)=0`

x² = 4 or x² = 1

1. x = ±√4 = -2 or 2
2. x = ±√1 = -1 or 1

Since x > 0, the negative integers are rejected and the solutions to this equations are x = 1 and x = 2

Answer 2

x=0,1,±2

Explanation:

x^3(x^2-5)=-4x

x^2(x^2-5)=-4

Take x^2=a, we have

a*(a-5)=-4, a^2-5a+4=0, (a-1)(a-4)=0, a=1,4

x^2=0, 1, 4. x=0,1,±2