Question

Given that for the water leakage n=100 Σx=31,353 and Σx^2 = 10687041 calculate the simple mean.​

Answer 1

`\bar x = ( \sum x)/(n) \\ \\ \bar x = (31353)/(100) \\ \\ \bar x = 313.53`

Answer 2

Hello,

Explanation:

`n=100\\\\\displaystyle \sum_(i=1)^(100)x_i=31.353\\\\\\\overline{x}=(\displaystyle \sum_(i=1)^(100)x_i)/(n) =(31.353)/(100) =\boxed{0.31353}\\\\`