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2 votes
Intergrate x×(x²-3)³

1 Answer

4 votes

Answer:
\large \boldsymbol{(1)/(8 ) (x^2-3)^4+c}

Explanation:


\displaystyle \large \boldsymbol{} \int\limits {x(x^2-3)^2 } \, dx =\int\limits (1)/(2) {} \, (x^2-3)' (x^2-3)^3 dx =(1)/(8) (x^2-3)^4+c

User Barmic
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