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If x = a sin teta and y = b cos teta

Find the value of b^2x^2+ a^2y^2


Plssss plsss helppp

User Ccalvert
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1 Answer

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  • x= a sin theta
  • y=b sin theta


\\ \sf\longmapsto b^2x^2+a^2y^2


\\ \sf\longmapsto b^2(asin\Theta)^2+a^2(bcos\Theta)^2


\\ \sf\longmapsto b^2a^2sin^2\Theta+a^2b^2cos^2\Theta


\\ \sf\longmapsto a^2b^2(sin^2\Theta+cos^2Theta)


\\ \sf\longmapsto a^2+b^2(1)


\\ \sf\longmapsto a^2b^2

User Potatopeelings
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