Answer:
![x=3, x=(3)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/l9gx3nnxf72irqqb5go3d4uex3i6onxioo.png)
Explanation:
![\left(x-3\right)\left(2x-3\right)=0](https://img.qammunity.org/2022/formulas/mathematics/high-school/v7xd1nss693j2k4ux0pixikrrpx25mq5uz.png)
The zero product theorem will be used here to solve this non-linear problem.
means that in the original equation, each variable component must be set to zero.
![\begin{cases} x-3=0\\2x -3=0\end{cases}](https://img.qammunity.org/2022/formulas/mathematics/high-school/x8dl3ocblup0xvs7hnzhkcu04ogswmk5rl.png)
To solve this linear equation, we need to group all of the variable terms on one side of the equation and all of the constant terms on the other.
so, -3 will be moved to the right side
Notice that when a term moves from one side of the equation to the other, it changes sign.
![\begin{cases} (x-3)+3=3\\(2x-3)+3=3 \end{cases}](https://img.qammunity.org/2022/formulas/mathematics/high-school/wcyppc8axs9yf679ibwrkqo07jsioz731v.png)
![x\left \{ 3,(3)/(2) \}](https://img.qammunity.org/2022/formulas/mathematics/high-school/3h23g3he4ue7gz6dfqd7tx2aef5l841h4c.png)
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