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Verify the identity algebraically:
Csc(-x)tanx =-secx

1 Answer

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Explanation:

Recall that


\sin(-x) = -\sin x

Therefore,


\csc(-x) = (1)/(\sin(-x)) = -(1)/(\sin x)

so


\csc(-x)\tan x = \left(-(1)/(\sin x)\right)\left((\sin x)/(\cos x)\right)


\:\:\:\:\:\:\:\:\:= -(1)/(\cos x) = -\sec x

User Eduard Dubilyer
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