Question

Solve the following system of equations for x: xy = 6
3y = x - 3

Answer 1

B

Explanation:

rearrange 3y = x-3 as x=3y+3 sub in for x in xy=6

(3y+3)(y)=6

solve by factoring 3y^2+3y-6=0

3(y-1)(y+2) = 0

y= 1, -2

sub y back in to either equation but for ease xy=6

x(1)=6 = 6

x(-2)=6 = -3