72.5k views
0 votes
The sum of the first n terms of an arithmetic series is 2n(n+3).

Find the first term of the series using the formula n/2(2a+(n-1)d)

User Mustkeem K
by
8.3k points

1 Answer

3 votes

Answer:

Sum:


{ \bf{S _(n) = (n)/(2) (2a + (n - 1)d) }} \\ \\ { \sf{2n(n + 3) = (n)/(2)(2a + (n - 1)d) }} \\ \\ { \sf{4 {n} + 12=2a + (n - 1)d }} \\ { \sf{2a = 4n - nd + d + 12}} \\ { \sf{2a = n(4 - d) + 12 + d}} \\ { \sf{a = (1)/(2)(n(4 - d) + 12 + d) }}

User Kofriel
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories