Question

A rectangle has a length of 38 meters less than 8 times its width. If the area of the rectangle is 4050 square meters, find the length of the rectangle.

Answer 1

Let

• width be x
• Length=8x-38
• Area=4050m^2

We know

`\boxed{\sf Area =Length* Width}`

`\\ \sf\longmapsto x(8x-38)=4050`

`\\ \sf\longmapsto 8x^2-38x=4050`

`\\ \sf\longmapsto 8x^2-38x-4050=0`

• By solving

`\\ \sf\longmapsto x=(81)/(4)\:or\:x=25`

• Take x as 25

`\\ \sf\longmapsto Length=8x-38=8(25)-38=200-38=162m`