155,796 views
40 votes
40 votes
3. A colony of ants triple every day. If the colony has 10 insects today, How many will be

present in 30 days?

User Jared Drake
by
2.8k points

2 Answers

8 votes
8 votes

Answer:

I think the answer is 900

Explanation:

10 x 3 = 30

30 x 30 = 900

Hope you have a wonderful day!

(Sorry if it is incorrect)

User Jtb
by
3.0k points
8 votes
8 votes

Answer:


6.86 * 10^(14) \textsf{ (nearest hundredth)}

Explanation:

If a colony of ants triples every day and initial number of insects was 10 then:

Day 1 = 10

Day 2 = 3 × 10 = 30

Day 3 = 3 × 30 = 90

etc.

let t = number of days

let n = number of insects


n = 10 \cdot 3^(t-1)

So when t = 30:


n = 10 \cdot 3^(30-1)


n = 6.86 * 10^(14) \textsf{ (nearest hundredth)}

User Astax
by
2.8k points