Question

The perimeter of a rectangle is 56 feet and

its area is 192 square feet. What are the
dimensions of the rectangle?

Answer 1

Explanation:

P = 2(L + W)

Area = L*W

Area = 192

(L + W)*2 = 56

L+W = 28

L = 28 - W

W*(28 - W) = 192

28W - w^2 = 92

-w^2 + 28w - 192 = 0

w^2 - 28w + 192 = 0

This factors into

(w - 12)(w - 16) = 0

w - 12 = 0

w = 12

L = 28 - 12 = 16