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4(6a + 2b^2) - 1/3 (27b^2 - 15a)
if a = -2 and b = 3

1 Answer

1 vote

Answer:


4(6a + 2b^2) - 1/3 (27b^2 - 15a)

a = -2

b = 3


4\left(6\left(-2\right)+2^2\right)-1/3\left(27\left(3\right)^2-15\left(-2\right)\right)

Follow the PEMDAS order of operations:-

  • Parentheses
  • Exponents
  • Multiplication or Division
  • Addition or Subtraction


4\left(6\left(-2\right)+2^2\right)

calculate within Parentheses


6\left(-2\right)+2^2


2^(2) =4


6(-2)=-12

Add:-


-12+4=-8


4\left(-8\right)-1/3\left(27\left(3\right)^2-15\left(-2\right)\right)

calculate within Parentheses:-


27\left(3\right)^2-15\left(-2\right)


(3)^(2) =9


27*9=243


243-15\left(-2\right)


15(-2)=-30


243-\left(-30\right)


=273


4\left(-8\right)-1/3\cdot \:273

Multiply:-


4\left(-8\right)=-32


-32-1/3\cdot \:273


1/3*273=91


=-32-91


=-123

OAmalOHopeO

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