Question

*Write a linear equation that goes through the points (-2,6) and (1,1).

Answer 1

Equation of the line is 3y = -5x + 8

Explanation:

Slope:

`{ \bf{m = (y _(2) - y _(1) )/(x _(2) - x _(1) ) }}`

substitute:

`{ \sf{m = (1 - 6)/(1 - ( - 2)) }} \\ { \sf{m = - (5)/(3) }}`

General equation of a line:

`{ \boxed{ \pmb{y = mx + b}}}`

b is the y-intercept.

Consinder point (1, 1):

`{ \sf{1 = ( - (5)/(3) * 1) + b}} \\ { \sf{b = (8)/(3) }}`

Substitute:

`{ \sf{y = - (5)/(3) x + (8)/(3) }} \\ \\ { \sf{3y = - 5x + 8}}`