Answer:

Explanation:
The Law of Sines is a property that relates the sides and angles of any triangle. This property states the following:

Where (A), (B), and (C) are the angles of the triangles. The sides (a), (b), and (c) are the sides opposite their respective angles, (side (a) is the opposite angle (<A); side (b) is the opposite angle (<B); and side (c) is the opposite angle (<C)). Substitute the given information into the formula and solve for the unknown:


Remove the parts of the equation that are not relevant to the problem,


Take the cross product of the proportion,


Inverse operations,


