Question

Consider a hard disk with the following specifications :
3.5 in diameter

Answer 1

usable capacity = 10 GB

Number of cylinders = 256

Block size = 4 KB

(1)Bytes in each cylinder = (10*230)/(256) = (10*222) = 40 MegaBytes

(2)Number of Blocks in each cylinder = (10*222)/(212) = 10K

(3)capacity of one track = 40 MegaBytes/(10*2) = 2 MB

Rotation speed = 3840 RPM

Number of rotations per second = 3840/60 = 64

Transfer rate = (2*64) = 128 MB/sec

Step-by-step explanation: