Question

Rhea and John have two trays of eggs with a total of 40 eggs. While bringing the eggs home, 8 eggs from Rhea's tray were broken, and 10 eggs from John's tray were broken. The product of the number of eggs left in each tray is no more than 125. Write an inequality that describes the relationship between the number of eggs each one has. If Rhea now has more eggs than John left in her tray, what is the least number of eggs that Rhea could have initially had?

Answer 1

Answer: (R - 8) x (J - 10) ≤ 125, Rhea had 20 eggs in the beginning

Explanation:

Let Rhea be R

Let John be J

R + J = 40

while coming home, 8 of R's eggs break, and 10 of J's eggs break.

.: (R - 8) x (J - 10) ≤ 125 is the inequality you can use to represent the situation.

The problem now says that after R and J lose eggs, R > J

between them, there were 40 eggs to begin with. Now the problem asks us what is the least number of eggs R could have, by which even after losing 8, she is still greater than J.

If we say that they both had equal eggs to begin with, then after losing their respective eggs, R will have 12, and J will have 10. In this scenario, R > J by 2. And this is our answer, as eggs can only come in whole numbers, not fractions or decimals.