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The length of a rectangle is twice its width. If the area of the rectangle is 72in², find its perimeter

User RmR
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1 Answer

2 votes

Let breadth be x

  • Length=2x


\\ \sf\longmapsto Area=Length* Breadth


\\ \sf\longmapsto 72=2x(x)


\\ \sf\longmapsto 2x^2=72


\\ \sf\longmapsto x^2=(72)/(2)


\\ \sf\longmapsto x^2=36


\\ \sf\longmapsto x=√(36)


\\ \sf\longmapsto x=6

  • Length=6×2=12in
  • Breadth=6in


\\ \sf\longmapsto Perimeter=2(L+B)


\\ \sf\longmapsto Perimeter=2(12+6)


\\ \sf\longmapsto Perimeter=2(18)


\\ \sf\longmapsto Perimeter=36in

User Vegashacker
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