Question

A and B are squares. The length of one side of square A is 4. The length of one side of square B is twice the length of a side of square A. What is the average (mean) area of the 2 squares?

Answer 1

40

Explanation:

So square A has a side of 4, therefore its area is 16 because you square the side length.

Square B has a side of 2 times Square A's side. So Square B has sidelength 8 as 4*2 = 8.

If Square B has side length 8, it has an area of 64.

The average is found by adding the two area and then dividing by 2. So,

64 + 16 = 80

80/2 = 40