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1 vote
What is the solution to each system

3) y=3x+1
3x+y=1
4) y=2x+1
y=2x+4
5) y= -5x+1
y=2x+4

1 Answer

4 votes

Answer:

3)x=0 y=1

Explanation:

3) y=3x+1

3x+y=1

y=1-3x

1-3x=3x+1

1-1=3x+3x

0=6x

x=0

by substitute in 1

y=3x+1

y=3*0+1

y=1

5) -5x+1=2x+4

-5x-2x=4-1

-7x=3

x=-3/7

by substitute in (y=2x+4)

y=2*-3/7+4

=25/7

User Tito Nobre
by
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