Question

Dy/dx(2x^2+2y^2-3x+2y=1)​

Answer 1

`{ \bf{ (dy)/(dx) = (3 - 4x)/(4y + 2) }}`

Explanation:

`{ \sf{ (dy)/(dx) (2 {x}^(2) + 2 {y}^(2) - 3x + 2y = 1) }} \\ \\ { \sf{4x + 4y (dy)/(dx) - 3 + 2 (dy)/(dx) = 0 }} \\ \\ { \sf{ 4y(dy)/(dx) + 2 (dy)/(dx) = 3 - 4x }} \\ \\ { \sf{ (dy)/(dx)(4y + 2) = 3 - 4x }} \\ \\ { \sf{ (dy)/(dx) = (3 - 4x)/(4y + 2) }}`

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