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Write x2 − 2x − 3 = 0 in the form (x − a)2 = b, where a and b are integers. (1 point) (x − 4)2 = 3 (x − 3)2 = 2 (x − 2)2 = 1 (x − 1)2 = 4

User Edik
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Answer:

Answer is (x - 1)² = 4

Explanation:


{ \tt{ {x}^(2) - 2x - 3 = 0}} \\

By completing squares:


{ \tt{ {x}^(2) - 2x + { ((2)/(2) )}^(2) - 3 - {( (2)/(2)) }^(2) = 0 }} \\ { \tt{( {x}^(2) - 2x + 1) = 4}} \\ { \tt{(x - 1) {}^(2) = 4 }}


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User Duncan Lukkenaer
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