Question

What is the distance between the following points?

y
>
2 3 4 5 6 7 8 9
-2-
.
-4
-5
-6
-7+
-8
-9

Answer 1

Given Points

• ⇛ 2 , -3 ( x = 2 and y = -3 )

• ⇛ 8 , -9 ( x= 8 and y = -9 )

Using Formula

`\begin{gathered} {\underline{\boxed{ \rm {\red{ Distance \: = \: \sqrt{(x_2 \: - \: x_1) ^(2) \: + \:(y_2 \: - \: y_1)} }}}}}\end{gathered}`

Substuting the values

`\bf \longrightarrow \:Distance \: = \: \sqrt{ \bigg(8 \: - \: 2 \bigg) ^(2) \: + \: \bigg( - 9 \: - \: (- 3) \bigg)^(2) }`

`\bf \longrightarrow \:Distance \: = \: \sqrt{ \bigg(8 \: - \: 2 \bigg) ^(2) \: + \: \bigg( - 9 \: + \: 3 \bigg)^(2) }`

`\bf \longrightarrow \:Distance \: = \: \sqrt{ (6 ) ^(2) \: + \:( - 6 )^(2) }`

`\bf \longrightarrow \:Distance \: = \: √( (36 ) \: + \:( 36 ) )`

`\bf \longrightarrow \:Distance \: = \: √(72)`

`\bf \longrightarrow \:Distance \: = \: 8.485281`

Approximate distance = 8.4

‌

‌

Hence , the distance between 2 points is

8.4 units

Answer 2

Point are

• (2,-3)
• (8,-9)

Using distance formula

`\\ \sf\longmapsto √((x_2-x_1)^2+(y_2-y_1)^2)`

`\\ \sf\longmapsto √((8-2)^2+(-9+3)^2)`

`\\ \sf\longmapsto √(6^2+(-6)^2)`

`\\ \sf\longmapsto √(36+36)`

`\\ \sf\longmapsto √(72)`

`\\ \sf\longmapsto 8.2units`