Question

There is a dropping of a coconut of 2kg mass. the speed of the coconut at the moment before it hits the ground is 40m s-1.

calculate the kinetic energy of the coconut at the moment.

Answer 1

• Mass=2kg
• Velocity=40m/s

We know

`\boxed{\sf K.E=(1)/(2)mv^2}`

• m denotes to mass
• v denotes to velocity

`\\ \sf\longmapsto K.E=(1)/(2)* 2* 40^2`

`\\ \sf\longmapsto K.E=40^2`

`\\ \sf\longmapsto K.E=1600J`