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Write the standard form of the equation of the circle with center (8,−1) that passes through the point (6,7)

User Corydoras
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1 Answer

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Answer:

(x - 8)^2 + (y + 1)^2 = 68

Explanation:

The standard form of the equation of the circle with center (8,−1) is :

(x - 8)^2 + (y + 1)^2 = R^2

If the circle passes through the point (6,7) that means that the point (6,7) is a solution of the equation and we can replace (x,y) with (6,7) to find R.

User RVG
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