Question

HELPPP!!!

find the area of a triangle with a height of 9cm and a base of 5 cm

Answer 1

`\begin{gathered} {\underline{\boxed{ \rm {\red{Area \: \: of \: \: triangle \: = \: (1)/(2) \: * \: base \: * \: height}}}}}\end{gathered}`

• Base of triangle = 5 cm.

• Height of triangle is 9 cm.

Solution

`\bf \longrightarrow \:Area \: \: of \: \: triangle \: = \: (1)/(2) \: * \: 5 \: cm \: * \: 9 \: cm`

`\bf \longrightarrow \:Area \: \: of \: \: triangle \: = \: (1)/(2) \: * \: 45 \: cm`

`\bf \longrightarrow \:Area \: \: of \: \: triangle \: = \: \frac{45 \: {cm}^(2) }{2} \: \\`

`\bf \longrightarrow \:Area \: \: of \: \: triangle \: = \: \cancel(45)/(2) \: \: ^{22.5 \: {cm}^(2) } \: \\`

`\bf \longrightarrow \:Area \: \: of \: \: triangle \: = \: 22.5 \: {cm}^(2)`

Hence , the area of triangle is 22.5 cm²

Answer 2

A = 22.5 cm^2

Explanation:

The area of a triangle is

A = 1/2 bh where b is the base and h is the height

A = 1/2(5)(9)

A = 45/2

A = 22.5 cm^2