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What is the minimum value of force acting between two charges placed at 1 m apart from each other? (a)Ke² (b)Ke (c)Ke/4 (d)Ke² /2
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What is the minimum value of force acting between two charges placed at 1 m apart from each other?

(a)Ke²
(b)Ke
(c)Ke/4
(d)Ke² /2

User Freeek
by
3.4k points

1 Answer

4 votes

Answer:

Ke²

Step-by-step explanation:

So,

q1 = e

q2 = e

r = 1m

By coulumb's law,

F = K (q1q2/r²)

F = K (e)(e)/(1)²

F = Ke²

Option(a)

User ZiGi
by
3.5k points
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